IPL 2021: Ravindra Jadeja remained unbeaten after scoring 62 runs. (CSK Twitter)
Ravindra Jadeja played an aggressive innings in the IPL (IPL 2021), taking Chennai Super Kings (CSK) to a strong position. He hit 5 sixes in one over of Harshal Patel.
After 19 overs, CSK’s score was 154 runs for 4 wickets. In such a situation, it seemed that the Chennai team would reach a maximum of 170 runs. But on the first two balls of the 20th over, Jadeja hit a deep midwicket six off Harshal’s ball. The third ball Harshal threw a fulltoss and the umpire gave it a nooble. Jadeja also sent it for a six outside the boundary. That is, 19 runs were scored on the first two balls.
4 sixes off 4 balls, 7 balls bowled in the last over.
On the next ball, Jadeja again hit a six off Harshal Patel. In this way, Jadeja had hit 4 sixes in 4 balls. There was also a Nobol among it. On the fourth ball, Jadeja took two runs. Jadeja hit a six on the fifth ball and a four on the last ball. In this way, Harshal Patel gave a total of 37 runs in the last over. He took 3 wickets for 51 runs in 4 overs in the match. CSK set a big score of 191 runs for 4 wickets in 20 overs.Also read: IPL 2021: Punjab Kings eye third win, KKR would like to regain momentum after 4 consecutive defeats
Gayle scored 37 runs in Parameswaran’s over.
Harshal Patel threw the most expensive over jointly in the IPL. Earlier in 2011, Parameshwar, playing with the Kochi Tuskers, had also given 37 runs in an over. Chris Gayle, playing from RCB, hit 4 sixes and 3 fours in the over. Parmeshwar had to throw 7 balls due to a no ball.